Optimal. Leaf size=248 \[ -\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}-\frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}}+\frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}} \]
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Rubi [A]
time = 0.18, antiderivative size = 248, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 9, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.474, Rules used = {49, 52, 65,
313, 230, 227, 1214, 1213, 435} \begin {gather*} \frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\text {ArcSin}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}}-\frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\text {ArcSin}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}} \end {gather*}
Antiderivative was successfully verified.
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Rule 49
Rule 52
Rule 65
Rule 227
Rule 230
Rule 313
Rule 435
Rule 1213
Rule 1214
Rubi steps
\begin {align*} \int \frac {(a+b x)^{5/2}}{(c+d x)^{9/4}} \, dx &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}+\frac {(2 b) \int \frac {(a+b x)^{3/2}}{(c+d x)^{5/4}} \, dx}{d}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {\left (12 b^2\right ) \int \frac {\sqrt {a+b x}}{\sqrt [4]{c+d x}} \, dx}{d^2}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}-\frac {\left (24 b^2 (b c-a d)\right ) \int \frac {1}{\sqrt {a+b x} \sqrt [4]{c+d x}} \, dx}{5 d^3}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}-\frac {\left (96 b^2 (b c-a d)\right ) \text {Subst}\left (\int \frac {x^2}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 d^4}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}+\frac {\left (96 b^{3/2} (b c-a d)^{3/2}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 d^4}-\frac {\left (96 b^{3/2} (b c-a d)^{3/2}\right ) \text {Subst}\left (\int \frac {1+\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}{\sqrt {a-\frac {b c}{d}+\frac {b x^4}{d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 d^4}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}+\frac {\left (96 b^{3/2} (b c-a d)^{3/2} \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1+\frac {b x^4}{\left (a-\frac {b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 d^4 \sqrt {a+b x}}-\frac {\left (96 b^{3/2} (b c-a d)^{3/2} \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {1+\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}{\sqrt {1+\frac {b x^4}{\left (a-\frac {b c}{d}\right ) d}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 d^4 \sqrt {a+b x}}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}+\frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}}-\frac {\left (96 b^{3/2} (b c-a d)^{3/2} \sqrt {\frac {d (a+b x)}{-b c+a d}}\right ) \text {Subst}\left (\int \frac {\sqrt {1+\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}}{\sqrt {1-\frac {\sqrt {b} x^2}{\sqrt {b c-a d}}}} \, dx,x,\sqrt [4]{c+d x}\right )}{5 d^4 \sqrt {a+b x}}\\ &=-\frac {4 (a+b x)^{5/2}}{5 d (c+d x)^{5/4}}-\frac {8 b (a+b x)^{3/2}}{d^2 \sqrt [4]{c+d x}}+\frac {48 b^2 \sqrt {a+b x} (c+d x)^{3/4}}{5 d^3}-\frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} E\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}}+\frac {96 b^{5/4} (b c-a d)^{7/4} \sqrt {-\frac {d (a+b x)}{b c-a d}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{b} \sqrt [4]{c+d x}}{\sqrt [4]{b c-a d}}\right )\right |-1\right )}{5 d^4 \sqrt {a+b x}}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 4 in
optimal.
time = 10.06, size = 73, normalized size = 0.29 \begin {gather*} \frac {2 (a+b x)^{7/2} \left (\frac {b (c+d x)}{b c-a d}\right )^{9/4} \, _2F_1\left (\frac {9}{4},\frac {7}{2};\frac {9}{2};\frac {d (a+b x)}{-b c+a d}\right )}{7 b (c+d x)^{9/4}} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {\left (b x +a \right )^{\frac {5}{2}}}{\left (d x +c \right )^{\frac {9}{4}}}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (a + b x\right )^{\frac {5}{2}}}{\left (c + d x\right )^{\frac {9}{4}}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a+b\,x\right )}^{5/2}}{{\left (c+d\,x\right )}^{9/4}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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